Dec 10, 2013

Mathematica advanced intro

No comments:

Nov 17, 2013

EMIS ELibM: Mathematical Collections and Conference Proceedings

http://www.emis.de/proceedings/index.html

No comments:

Nov 16, 2013

Differential Geometry: A beginner's journey.

A good summary:
Applications of Differential Geometries:

Helping to solve other unsolved maths problem:

http://en.wikipedia.org/wiki/List_of_unsolved_problems_in_mathematics

Possible applications of differential geometry concepts:

  1. Elementary Geometry

  2. Center of an arc determined with straightedge and compass.
  3. Surface areas: Circle, trapezoid, triangle, sphere, frustum, cylinder, cone...
  4. Power of a point  with respect to a circle.
  5. Euler's line  goes through the orthocenter, the centroid and the circumcenter.
  6. Euler's circle  is tangent to the incircle and the excircles  (Feuerbach, 1822).
  7. Barycentric coordinates & trilinears  examplify  homogeneous coordinates.
  8. Elliptic arc: Length of the arc of an ellipse between two points.
  9. Perimeter of an ellipse. Exact formulas and simple ones.
  10. Surface of an ellipse.
  11. Volume of an ellipsoid  (either a spheroid or a scalene ellipsoid).
  12. Surface area of a spheroid  (oblate or prolate ellipsoid of revolution).
  13. Quadratic equations in the plane describe ellipses, parabolas, or hyperbolas.
  14. Centroid of a circular segment. Find it with Guldin's (Pappus) theorem.
  15. Parabolic arc of given extremities  with a prescribed apex between them.
  16. Focal point of a parabola. y = x 2 / 4f (where f is the focal distance).
  17. Parabolic telescope: The path from infinity to focus is constant.
  18. Make a cube go through a hole in a smaller cube.
  19. Octagon: The relation between side and diameter.
  20. Constructible regular polygons  and constructible angles (Gauss).
  21. Areas of regular polygons of unit side: General formula & special cases.
  22. For a regular polygon of given perimeter, the more sides the larger the area.
  23. Curves of constant width: Reuleaux Triangle and generalizations.
  24. Irregular curves of constant width. With or without any circular arcs.
  25. Solids of constant width. The three-dimensional case.
  26. Constant width in higher dimensions.
  27. Fourth dimension. Difficult to visualize, but easy to consider.
  28. Volume of a hypersphere and hyper-surface area, in any dimensionality.
  29. Hexahedra. The cube is not the only polyhedron with 6 faces.
  30. Descartes-Euler Formula: F-E+V=2 but restrictions apply.

    Topology:

  31. Metric spaces:  The motivation behind more general  topological  spaces.
  32. Abstract topological spaces  are defined by calling some subsets  open.
  33. Closed sets  are sets (of a topological space) whose complements are open.
  34. Subspace F of E:  Its open sets are the intersections with F of open sets of E.
  35. Separation axioms:  Flavors of topological spaces, according to  Trennung.
  36. Compactness of a topological space:  Any open cover has a  finite subcover.
  37. Real-valued continuous functions on compact sets  attain their extremes.
  38. Borel sets.  Tribes  form the topological foundation for  measure theory.
  39. Locally compact sets  contain a  compact neighborhood  of every point.
  40. General properties of sequences  characterize topological properties.
  41. Continuous functions  let the  inverse image  of any open set be open.
  42. Restrictions remain continuous.  Continuous extensions may be impossible.
  43. The product topology  makes projections continuous on a cartesian product.
  44. Connected sets  can't be split by open sets.  The empty set  is  connected.
  45. Path-connected sets  are a special case of  connected sets.
  46. Homeomorphic sets.  An  homeomorphism  is a  bicontinuous function.
  47. Arc-connected spaces are path-connected.  The converse need not be true.
  48. Homotopy:  A progessive transformation of a  function  into another.
  49. The fundamental group:  The homotopy classes of all loops through a point.
  50. Homology and Cohomology.  Poincaré duality.
  51. Descartes-Euler Formula:  F-E+V = 2, but restrictions apply.
  52. Euler Characteristic:   c   (chi)  extended beyond its traditional definition...
  53. Winding number  of a continuous planar curve about an outside point.
  54. Fixed-point theorems  by  Brouwer,  Shauder  and  Tychonoff.
  55. Turning number  of a planar curve with a well-defined oriented tangent.
  56. Real projective plane  and Boy's surface.
  57. Hadwiger's  additive continuous functions of d-dimensional rigid bodies.
  58. Eversion of the sphere.  An homotopy  can  turn a sphere inside out.
  59. Classification of surfaces:  "Zero Irrelevancy Proof" (ZIP) by J.H. Conway.
  60. Braid groups:  Strands, braids and pure braids.

    Completeness:

  61. Complete metric space:  A space in which all Cauchy sequences converge.
  62. Flawed alternatives to completeness.
  63. Banach spaces  are complete normed vector spaces.
  64. Fréchet spaces  are generalized Banach spaces.

    Fractal Geometry:

  65. Fractional exponents  were first conceived by Nicole d'Oresme (c. 1360).
  66. The von Koch curve (and  snowflake):  Dimension of self-similar objects.
  67. Hausdorff dimension is revealed by a covering with balls of radius  < e.
  68. The Julia set and the Fatou set of an analytic function  are complementary.
  69. The Mandelbrot set was so named by  Adrien Douady  &  John H. Hubbard.

    Angles and Solid Angles:

  70. Planar angles  (from one direction to another)  are  signed  quantities.
  71. Bearing:  Unless otherwise specified, this is the angle  west of north.
  72. Solid angles  are to spherical patches what planar angles are to circular arcs.
  73. Circular measures:  Angles and solid angles aren't quite dimensionless...
  74. Solid angle formed by a trihedron :   Van Oosterom & Strackee  (1983).
  75. Solid angle subtended by a rhombus.  Apex of a right  rhombic pyramid.
  76. Formulas for solid angles  subtended by patches with simple shapes.
  77. Right ascension and declination.  Precession of celestial coordinates  (a,d).

    Curvature and Torsion:

  78. Curvature of a planar curve:  Variation of inclination with distance  dj/ds.
  79. Curvature and torsion  of a three-dimensional curve.
  80. Distinct curvatures and  geodesic  torsion  of a curve drawn on a surface.
  81. The two fundamental quadratic forms  at a point of a parametrized surface.
  82. Lines of curvature:  Their  normal  curvature is extremal at every point.
  83. Geodesic lines.  Least length is achieved with  zero geodesic curvature.
  84. Meusnier's theorem:  Tangent lines have the same  normal curvature.
  85. Gaussian curvature of a surface.  The  Gauss-Bonnet theorem.
  86. Parallel-transport of a vector around a loop.  Holonomic angle of a loop.
  87. Total curvature of a curve.  The Fary-Milnor theorem for knotted curves.
  88. Linearly independent components  of the  Riemann curvature tensor.

    Planar Curves:

  89. Cartesian equation of a straight line:  passing through two given points.
  90. Confocal Conics:  Ellipses and hyperbolae sharing the same pair of  foci.
  91. Spiral of Archimedes:  Paper on a roll, or groove on a vinyl record.
  92. Hyperbolic spiral:  The inverse of the  Archimedean spiral.
  93. Catenary:  The shape of a thin chain under its own weight.
  94. Witch of Agnesi.  How the versiera (Agnesi's cubic) got a weird name.
  95. Folium of Descartes.
  96. Lemniscate of Bernoulli:  A quartic curve shaped like the  infinity symbol.
  97. Along a Cassini oval, the product of the distances to the two foci is constant.
  98. Limaçons of Pascal:  The cardioid  (unit epicycloid) is a special case.
  99. On a Cartesian oval, the weighted average distance to two poles is constant.
  100. The envelope of a family of curves  is everywhere tangent to one of them.
  101. The evolute of a curve  is the locus of its centers of curvature.
  102. Involute of a curve:  Trajectory of a point of a line  rolling  on that curve.
  103. Parallel curves  share their normals, along which their distance is constant.
  104. The nephroid  (or  two-cusped epicycloid )  is a  catacaustic  of a circle.
  105. Freeth's nephroid:  A special  strophoid  of a circle.
  106. Bézier curves  are algebraic splines.  The cubic type is the most popular.
  107. Piecewise circular curves:  The traditional way to specify curved forms.
  108. Intrinsic equation  [curvature as a function of arc length]  may have  spikes.
  109. The quadratrix (trisectrix) of Hippias squares the circle and trisects angles.
  110. The parabola  is  constructible  with straightedge and compass.
  111. Mohr-Mascheroni constructions  use the compass alone  (no straightedge).




Collection of Mathematica articles:

http://demonstrations.wolfram.com/siteindex.html




No comments:

Nov 13, 2013

(good book) Lectures on Discrete and Polyhedral Geometry (Igor Pak Home Page)

1 comment:

Nov 9, 2013

A generalization of a number pattern from base 10 to base 16, and base 20, and base 32


First looking at the decimals number patterns:

12*9+3 : 111
123*9+4 : 1111
1234*9+5 : 11111
12345*9+6 : 111111
123456*9+7 : 1111111
1234567*9+8 : 11111111
12345678*9+9 : 111111111
123456789*9+10 : 1111111111

And the python generator for this:

def get_first(p1, mynum):
   
    p2 = p1 + str(mynum)
    n2 = int(p2) * 9 + (mynum+1)
    print "%s*9+%d : %d"%(p2,mynum+1, n2)
    get_first(p2, mynum+1)

 get_first("1", 2)
   
Can it be generalize to base 16?

Yes:

12*15+0x3 : 0x111
123*15+0x4 : 0x1111
1234*15+0x5 : 0x11111
12345*15+0x6 : 0x111111
123456*15+0x7 : 0x1111111
1234567*15+0x8 : 0x11111111
12345678*15+0x9 : 0x111111111L
123456789*15+0xa : 0x1111111111L
123456789a*15+0xb : 0x11111111111L
123456789ab*15+0xc : 0x111111111111L
123456789abc*15+0xd : 0x1111111111111L
123456789abcd*15+0xe : 0x11111111111111L
123456789abcde*15+0xf : 0x111111111111111L
123456789abcdef*15+0x10 : 0x1111111111111111L

And the program is:

def pattern_base16(p1, mynum):
    p2 = p1 + hex(int(str(mynum)))[2:]
    n2 = int(p2,16) * 15 + (mynum+1)
    print "%s*15+%s : %s"%(p2,hex(mynum+1), hex(n2))
    pattern_base16(p2, mynum+1)

 pattern_base16("1", 2)

And for base 20:

12*19+3 : 111
123*19+4 : 1111
1234*19+5 : 11111
12345*19+6 : 111111
123456*19+7 : 1111111
1234567*19+8 : 11111111
12345678*19+9 : 111111111
123456789*19+a : 1111111111
123456789a*19+b : 11111111111
123456789ab*19+c : 111111111111
123456789abc*19+d : 1111111111111
123456789abcd*19+e : 11111111111111
123456789abcde*19+f : 111111111111111
123456789abcdef*19+g : 1111111111111111
123456789abcdefg*19+h : 11111111111111111
123456789abcdefgh*19+i : 111111111111111111
123456789abcdefghi*19+j : 1111111111111111111
123456789abcdefghij*19+10 : 11111111111111111111

and the program is:

from baseconv import BaseConverter

 def base10_to_20(nos):
    base20 = BaseConverter('0123456789abcdefghij')
    return base20.encode(nos)

 def base20_to_10(mystring):
    base20 = BaseConverter('0123456789abcdefghij')
    return int(base20.decode(mystring))

 def pattern_base20(p1, mynum):
    p2 = p1 + base10_to_20(mynum)
    #print "p2=%s"%p2
    n2 = base20_to_10(p2) * 19 + (mynum+1)
    print "%s*19+%s : %s"%(p2, base10_to_20(mynum+1), base10_to_20(n2))
    pattern_base20(p2, mynum+1)

 pattern_base20("1", 2)

And for base 32:

12*31+3 : 111
123*31+4 : 1111
1234*31+5 : 11111
12345*31+6 : 111111
123456*31+7 : 1111111
1234567*31+8 : 11111111
12345678*31+9 : 111111111
123456789*31+a : 1111111111
123456789a*31+b : 11111111111
123456789ab*31+c : 111111111111
123456789abc*31+d : 1111111111111
123456789abcd*31+e : 11111111111111
123456789abcde*31+f : 111111111111111
123456789abcdef*31+g : 1111111111111111
123456789abcdefg*31+h : 11111111111111111
123456789abcdefgh*31+i : 111111111111111111
123456789abcdefghi*31+j : 1111111111111111111
123456789abcdefghij*31+k : 11111111111111111111
123456789abcdefghijk*31+l : 111111111111111111111
123456789abcdefghijkl*31+m : 1111111111111111111111
123456789abcdefghijklm*31+n : 11111111111111111111111
123456789abcdefghijklmn*31+p : 111111111111111111111111
123456789abcdefghijklmnp*31+q : 1111111111111111111111111
123456789abcdefghijklmnpq*31+r : 11111111111111111111111111
123456789abcdefghijklmnpqr*31+s : 111111111111111111111111111
123456789abcdefghijklmnpqrs*31+t : 1111111111111111111111111111
123456789abcdefghijklmnpqrst*31+u : 11111111111111111111111111111
123456789abcdefghijklmnpqrstu*31+v : 111111111111111111111111111111
123456789abcdefghijklmnpqrstuv*31+w : 1111111111111111111111111111111
123456789abcdefghijklmnpqrstuvw*31+10 : 11111111111111111111111111111111

And the program is:

from baseconv import BaseConverter

 def base10_to_32(nos):
        base32 = BaseConverter('0123456789abcdefghijklmnpqrstuvw')
        return base32.encode(nos)

 def base32_to_10(mystring):
        base32 = BaseConverter('0123456789abcdefghijklmnpqrstuvw')
        return int(base32.decode(mystring))

 def pattern_base32(p1, mynum):
    p2 = p1 + base10_to_32(mynum)
    #print "p2=%s"%p2
    n2 = base32_to_10(p2) * 31 + (mynum+1)
    print "%s*31+%s : %s"%(p2, base10_to_32(mynum+1), base10_to_32(n2))
    pattern_base32(p2, mynum+1)

The BaseConverter python module is downloaded following the two articles below:

http://stackoverflow.com/questions/2267362/convert-integer-to-a-string-in-a-given-numeric-base-in-python

https://bitbucket.org/semente/baseconv






No comments:

Oct 12, 2013

USA USAMO • Art of Problem Solving

No comments:

Aug 18, 2013

Mathematical Problems Lecture delivered before the International Congress of Mathematicians at Paris in 1900

No comments:

Aug 17, 2013

Project Euler Problem Nos 43

Original problem posted at:

http://projecteuler.net/problem=43

This is my solution to problem 43:

#!/usr/bin/python

### problem 43

import string

def get_divisible_set(n):
    myset=[]
    for i in range(2,999):
        if (i%n==0):
            myset.append(str(i).zfill(3))
            ###myset.append(str.format("%03d", i))
###n = '4'
###>>> print n.zfill(3)
###>>> '004'
    return myset

def check_adjoining_item(a, b):
    if ((a[1]==b[0])and(a[2]==b[1])):
        return 1
    else:
        return 0

def get_adjoining_set(seta, setb):
    myset=[]
    #### assuming setb is the smaller set....
    mylenb=len(setb)
    mylena=len(seta)
    for i in range(mylenb):
        for j in range(mylena):
            ###print seta[j], setb[i]
            mysettmp=set(seta[j])
            mysettmp=mysettmp.union(set(setb[i]))
            if (check_adjoining_item(seta[j], setb[i])==1) and (len(mysettmp)==4):
                myset.append((seta[j],setb[i]))
    return myset


myset17=get_divisible_set(17)
myset13=get_divisible_set(13)
myset11=get_divisible_set(11)

myset=get_adjoining_set(myset13, myset17)

nextset=[]
for i in range(len(myset)):
    #print myset[i]
    (a,b)=myset[i]
    tmp=[]
    mysettmp=set()
    tmp.append(a)
    tmpset=get_adjoining_set(myset11, tmp)
    if len(tmpset)>0:
        for j in range(len(tmpset)):
            (c,d)=tmpset[j]
            mysettmp=set(d)
            mysettmp=mysettmp.union(set(c))
            mysettmp=mysettmp.union(set(a))
            mysettmp=mysettmp.union(set(b))
            if len(mysettmp)==5:
                nextset.append((c,a,b))

print "aaaa"
print nextset

myset7=get_divisible_set(7)

nextset1=[]

for i in range(len(nextset)):
    (a,b,c)=nextset[i]
    tmp=[]
    mysettmp=set()
    tmp.append(a)
    tmpset=get_adjoining_set(myset7, tmp)
    if len(tmpset)>0:
        for j in range(len(tmpset)):
            (d,e)=tmpset[j]
            mysettmp=set(e)
            mysettmp=mysettmp.union(set(d))
            mysettmp=mysettmp.union(set(a))
            mysettmp=mysettmp.union(set(b))
            mysettmp=mysettmp.union(set(c))
            if len(mysettmp)==6:
                nextset1.append((d,e,b,c))

print "bbb"
print nextset1

myset5=get_divisible_set(5)

nextset2=[]

for i in range(len(nextset1)):
    (a,b,c,d)=nextset1[i]
    tmp=[]
    mysettmp=set()
    tmp.append(a)
    tmpset=get_adjoining_set(myset5, tmp)
    if len(tmpset)>0:
        for j in range(len(tmpset)):
            (e,f)=tmpset[j]
            mysettmp=set(f)
            mysettmp=mysettmp.union(set(e))
            mysettmp=mysettmp.union(set(a))
            mysettmp=mysettmp.union(set(b))
            mysettmp=mysettmp.union(set(c))
            mysettmp=mysettmp.union(set(d))
            if len(mysettmp)==7:
                nextset2.append((e,a,b,c,d))

print "bbb"
print nextset2

myset3=get_divisible_set(3)

nextset3=[]

for i in range(len(nextset2)):
    (a,b,c,d,e)=nextset2[i]
    tmp=[]
    mysettmp=set()
    tmp.append(a)
    tmpset=get_adjoining_set(myset3, tmp)
    if len(tmpset)>0:
        for j in range(len(tmpset)):
            (f,g)=tmpset[j]
            mysettmp=set(g)
            mysettmp=mysettmp.union(set(f))
            mysettmp=mysettmp.union(set(a))
            mysettmp=mysettmp.union(set(b))
            mysettmp=mysettmp.union(set(c))
            mysettmp=mysettmp.union(set(d))
            mysettmp=mysettmp.union(set(e))
            if len(mysettmp)==8:
                nextset3.append((f,a,b,c,d,e))

myset2=get_divisible_set(2)

nextset4=[]

for i in range(len(nextset3)):
    (a,b,c,d,e,f)=nextset3[i]
    tmp=[]
    mysettmp=set()
    tmp.append(a)
    tmpset=get_adjoining_set(myset2, tmp)
    if len(tmpset)>0:
        for j in range(len(tmpset)):
            (g,h)=tmpset[j]
            mysettmp=set(h)
            mysettmp=mysettmp.union(set(g))
            mysettmp=mysettmp.union(set(a))
            mysettmp=mysettmp.union(set(b))
            mysettmp=mysettmp.union(set(c))
            mysettmp=mysettmp.union(set(d))
            mysettmp=mysettmp.union(set(e))
            mysettmp=mysettmp.union(set(f))
            if len(mysettmp)==9:
                nextset4.append((g,a,b,c,d,e,f))

print "final ans"
print nextset4

Output from the python script:

[('160', '603', '035', '357', '572', '728', '289'), ('460', '603', '035', '357', '572', '728', '289'), ('106', '063', '635', '357', '572', '728', '289'), ('406', '063', '635', '357', '572', '728', '289'), ('130', '309', '095', '952', '528', '286', '867'), ('430', '309', '095', '952', '528', '286', '867')]

Or after rearranging the digits according to the rules in problem 43:

4160357289
1460357289
4106357289
1406357289
4130952867
1430952867

These are the six numbers that satisfy all the properties and will add up to the answer.



No comments:

Aug 15, 2013

Erich's Puzzle Palace

No comments:

“Happy Birthday, Euler!”, Project Euler, and Pants | Math Munch

No comments:

Aug 13, 2013

Physics World Cup Problems & Solutions (II)



  2. [PDF]

    pdf 1 - IYPT Archive

    archive.iypt.org/.../2011_4_Breaking_spaghetti_Belarus2_YP_answers_...‎
    Dear Reviewer,. Thank you for your review. I would like to explain some aspects in my paper and show the improvements which were made by me according to ...
  3. [PDF]

    THE LIQUID LIGTH GUIDE - IYPT Archive

    archive.iypt.org/iypt.../2010_4_Soap_film_Georgia_AB_full_reviews.pd...‎
    REVIEWS ON THE MANUSCRIPT [27]. Reviewer 1: I hereby recommend the manuscript # [27] for publication. There are some minor drawbacks, but they can be ...
  4. [PDF]

    Reviewer 1 - IYPT Archive

    archive.iypt.org/iypt_book/2011_5_Car_Croatia_NB_answers.pdf‎
    Response to REVIEWS ON THE MANUSCRIPT [5]. Reviewer 1: I have included a comment on limitations of solution before the final conclusion as suggested.
  5. [PDF]

    ranking after pf4 - IYPT

    2008.iypt.org/PDF/PF4.pdf‎
    Place. Team. PF1. PF2. PF3. PF4. PF5. Points. Team #. 1. Germany. 46.0. 48.7. 48.2. 47.0. 0.0. 189.9. 16. 2. Korea. 43.8. 47.9. 46.7. 44.1. 0.0. 182.5. 5. 3. Austria.
  6. [PDF]

    THE LIQUID LIGTH GUIDE - IYPT Archive

    archive.iypt.org/.../2011_4_Breaking_spaghetti_Slovakia_MV_TK_MH...‎
    REVIEWS ON THE MANUSCRIPT [16]. Reviewer 1: Introduction: The work suggests that spaghetti is more probable to break in a point where the bending ...
  7. [PDF]

    ranking after pf3 - IYPT 2008

    2008.iypt.org/PDF/PF3.pdf‎
    Place. Team. PF1. PF2. PF3. PF4. PF5. Points. Team #. 1. Germany. 46.0. 48.7. 48.2. 0.0. 0.0. 142.9. 16. 2. Korea. 43.8. 47.9. 46.7. 0.0. 0.0. 138.4. 5. 3. Austria.
  8. [PDF]

    Response to REVIEWS ON THE MANUSCRIPT [18 ... - IYPT Archive

    archive.iypt.org/.../2010_8_Liquid_light_guide_Croatia_UP_answers.pd...‎
    Response to REVIEWS ON THE MANUSCRIPT [18]. Thank you very much for reviewing my manuscript and for all suggestions. Reviewer 1: Thank you for the ...
  9. [PDF]

    THE LIQUID LIGTH GUIDE - IYPT Archive

    archive.iypt.org/iypt.../2010_6_Ice_Belarus_SK_s2_full_reviews.pdf‎
    REVIEWS ON THE MANUSCRIPT [24-2]. Reviewer 1: Comments: The current version of the article is much more understandable. The reviewer is satisfied with ...
  10. [PDF]

    After reading opinions and suggestions of the ... - IYPT Archive

    archive.iypt.org/iypt.../2010_2_Brilliant_pattern_Poland_LG_answers.p...‎
    After reading opinions and suggestions of the reviewers I decided to rewrite the whole article. As this year the limit for number of pages is 20 I expanded the ...
  11. [PDF]

    Thank you very much for reviewing my manuscript ... - IYPT Archive

    archive.iypt.org/iypt_book/2010_4_Soap_film_Croatia_UP_answers.pdf‎
    Response to REVIEWS ON THE MANUSCRIPT [19]. Thank you very much for reviewing my manuscript and for all suggestions. I reorganized some thing to ...
  12. [PDF]

    P Problem No 17 (2 Alexand 2010). “K der BAR ... - IYPT Archive

    archive.iypt.org/iypt.../2010_17_Kelvin's_dropper_Georgia_AB_v2.pdf‎
    Problem produc. 1. Kelv. In known device. Fig.1)[1 which someti device and ge. Let. It cons. (see Fi placed connec. When flow th adjuste inductio are c contain.
  13. [PDF]

    Preview for fight 5 - Group A

    results.iypt.org/IYPT2012/previews-5.pdf‎
    Stage 1: New Zealand, Iran, Australia. Problems left to challange: 1, 5, 9, 12, 17 a) rejected by Reporter: None b) presented by Reporter: 2 ,3 ,6 ,16 c) opposed ...
  14. [PDF]

    The Regulations of the International - IYPT

    www.iypt.org/images/b/bd/IYPT_Regulations_2011_Isfahan.pdf‎
    Jul 30, 2011 - The Regulations of the International. Young Physicists' Tournament. I. International Young Physicists' Tournament. The International Young ...
  15. [PDF]

    2 - IYPT Bratislava 2006

    2006.iypt.org/documents/Brigitte_Pagana-Hammer.pdf‎
    1. IYPT Requirements. Vienna, February 2006. Structure. • Problems. • Reasons. • Goals. • Realization. • Ongoing issues. • The Austrian position ...
  16. [PDF]

    STYLE SHEET FOR PAPERS IN THE PROCEEDINGS - IYPT Archive

    archive.iypt.org/iypt.../2010_17_Kelvin's_dropper_Georgia_AB_v1.pdf‎
    Problem No 17 (2. Problem produc. 1. Kelv. In known device. It was called someti device and ge. Let. It cons. (see Fi placed connec. When flow th adjuste.
  17. [PDF]

    Preview for fight 2 - Room A - IYPT

    results.iypt.org/IYPT2011/previews-2.pdf‎
    Stage 1: Bulgaria, Slovakia, Sweden. Problems left to challange: 1, 2, 3, 4, 6, 7, 8, 10, 11, 12, 13, 14, 16 a) rejected by Reporter: 15 b) presented by Reporter: 5.
  18. [PDF]

    Overview for Round: 1

    results.iypt.org/IYPT2012/roundresults-1.pdf‎
    Overview for Round: 1. Rank. Team. TSP = 1. Korea. 44.7 = 44.7. 2. Singapore. 40.1 = 40.1. 3. Russia. 38.7 = 38.7. 4. Slovakia. 38.5 = 38.5. 5. Chinese Taipei ...
  19. [PDF]

    Preview for fight 5 - Room A

    results.iypt.org/IYPT2011/previews-5.pdf‎
    Stage 1: Brazil, Ukraine, Bulgaria. Problems left to challange: 3, 6, 7, 10, 12 a) rejected by Reporter: 5 b) presented by Reporter: 1 ,8 ,13 ,15 c) opposed by ...
  20. [PDF]

    Round: 1, Room: Room A - IYPT

    results.iypt.org/AYPT2012/previews-1.pdf‎
    Stage 1: Freistadt, Belarus, Salzburg. Problems left to challange: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,. 16, 17 a) rejected by Reporter: None b) presented ...
  21. [PDF]

    Problems for the 26th IYPT 2013

    iypt.org/images/f/f6/problems2013.pdf‎
    Problems for the 26th IYPT 2013. There are more things in heaven and earth, Horatio,. Than are dreamt of in your philosophy. Shakespeare. 1. Invent yourself.
  22. [PDF]

    Download - IYPT

    iypt.org/images/a/a8/EC_October_2011.pdf‎
    International Organizing Committee. Young Physicists' Tournament. EC meeting. Minutes. October 28th – 30th 2011, Bad Saulgau. Present: Alan Allinson ...
  23. [PDF]

    Preview for fight 2 - Group A - IYPT

    results.iypt.org/IYPT2012/previews-2.pdf‎
    Stage 1: Nigeria, Belarus, Russia. Problems left to challange: 1, 3, 4, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,. 17 a) rejected by Reporter: None b) presented by ...
  24. [PDF]

    Odborná komisia - IYPT

    www.iypt.org/images/6/6f/EC_Nov_2012.pdf‎
    International Organizing Committee. Young Physicists' Tournament. EC meeting. Minutes. November 10th – 11th 2012, Taipei, Taiwan. Present: Alan Allinson ...
  25. [PDF]

    Preview for fight 3 - Room A - IYPT

    results.iypt.org/IYPT2011/previews-3.pdf‎
    Stage 1: Sweden, Korea, Czech Republic. Problems left to challange: 1, 2, 4, 6, 8, 9, 10, 12, 13, 14, 16 a) rejected by Reporter: 11 b) presented by Reporter: 3 , ...
  26. [PDF]

    Preview for fight 3 - Group A

    results.iypt.org/IYPT2012/previews-3.pdf‎
    Stage 1: United Kingdom, Slovakia,. Belarus. Problems left to challange: 2, 3, 5, 7, 10, 11, 12, 13, 14, 16, 17 a) rejected by Reporter: None b) presented by ...
  27. [PDF]

    Overview for Round: 3

    results.iypt.org/IYPT2012/roundresults-3.pdf‎
    Overview for Round: 3. Rank. Team. TSP = 1. Korea. 130.4 = 44.7 + 44.2 + 41.5. 2. Singapore. 126.8 = 40.1 + 42.7 + 44.0. 3. Germany. 118.4 = 35.4 + 38.2 + ...
  28. [PDF]

    IOC meeting Minutes - IYPT

    www.iypt.org/images/8/80/IOC_July_2011.pdf‎
    International Organizing Committee. Young Physicists' Tournament. IOC meeting. Minutes. July 30th 2011, Safavi Hotel, Esfahan, Iran. Agenda. The agenda ...
  29. [PDF]

    Round: 2, Room: Room A - IYPT

    results.iypt.org/AYPT2012/previews-2.pdf‎
    Stage 1: Bisch Gym, Seebacher Gym,. Voronezh. Problems left to challange: 2, 3, 4, 5, 7, 8, 9, 10, 11, 12, 13, 15, 16, 17 a) rejected by Reporter: None.
  30. [PDF]

    Round: 3 - IYPT

    results.iypt.org/AYPT2011/roundresults-3.pdf‎
    Round: 3. Rank. Team. TSP = 1. Seebacher Gymnasium Graz. 152.1 = 48.1 + 54.5 + 49.5. 2. Slovakia. 142.8 = 43.1 + 47.8 + 51.9. 3. Bischoefliches Gymnasium ...
  31. [PDF]

    Problems for the 27th IYPT 2014

    iypt.org/images/a/a8/problems2014.pdf‎
    Problems for the 27th IYPT 2014. Released by the IOC on August 1st, 2013. When throwing pebbles into water, watch the ripples;. Otherwise throwing the ...
  32. [PDF]

    IYPT 2012

    iypt.org/images/0/05/Problems2012.pdf‎
    IYPT 2012. 1. Gaussian cannon. A sequence of identical steel balls includes a strong magnet and lies in a nonmagnetic channel. Another steel ball is rolled.
  33. [PDF]

    Problems for IYPT 2011

    www.iypt.org/images/8/82/Problems_2011.pdf‎
    Problems for IYPT 2011. 1. Adhesive tape. Determine the force necessary to remove a piece of adhesive tape from a horizontal surface. Investigate the influence ...
  34. [PDF]

    Scoring Guidelines - IYPT

    www.iypt.org/images/4/43/scoring_guidelines.pdf‎
    Revised after IOC feedback and approved by EC on 2011-11-03. A report should include: • a presentation of the appropriate concepts, theories and principles of ...
  35. [PDF]

    Odborná komisia - IYPT

    iypt.org/images/5/54/IOC_July_2012.pdf‎
    International Organizing Committee. Young Physicists' Tournament. Annual IOC meeting, Stuttgart, Germany. Minutes. July 27th (21:05 ‒ 22:35), July 28th (9:07 ...
  36. [PDF]

    Tournament Annual IOC meeting, Alpenhotel Goessing ... - IYPT

    www.iypt.org/images/f/f8/IOC_July_2010.pdf‎
    Jul 17, 2010 - International Organizing Committee. Young Physicists' Tournament. Annual IOC meeting, Alpenhotel Goessing, Austria. Minutes. July 16th ...
  37. [PDF]

    ranking after the final - IYPT 2008

    2008.iypt.org/PDF/final.pdf‎
    IYPT 2008 - Croatia. Final ranking. First place: GERMANY. Second place: CROATIA. NEW ZEALAND. Third place: AUSTRIA. KOREA. POLAND. BELARUS.
  38. [PDF]

    Data not available yet. - IYPT

    results.iypt.org/test/roundresults-1.pdf‎
    Andreas Uller. NN NN. Ingomar Gutmann. Angel Usunov. Hildegard Urban-Woldron. Average: * [[3.0|3.0|3.0]|[2|1]. Problems: Voronezh. I. Emelianova. Slovakia.
  39. [PDF]

    THE LIQUID LIGTH GUIDE - IYPT Archive

    archive.iypt.org/.../2011_1_Adhesive_tape_Belarus_SK_editorial_remar...‎
    Page 1. SECOND EDITORIAL REMARK ON THE MANUSCRIPT [8]. Hook's law: Hooke's law. Possessive pronouns: its, not it's.
  40. [PDF]

    Problem submission form IYPT 2013

    www.iypt.org/images/f/f1/Submission_form.pdf‎
    Apr 30, 2012 - International Organizing Committee. Young Physicists' Tournament. Problem submission form IYPT 2013. Country. Author's name e-mail.
  41. [PDF]

    IYPT Call for Papers 2011

    iypt.org/images/b/b0/IYPT_Call_for_Papers_2011.pdf‎
    Aug 29, 2011 - IYPT: Call for Papers. Proceedings Book for 2011 and 2010. Would you like to have your IYPT project published in an international book?
  42. [PDF]

    There is a shuttle bus between Beijing airport to Tianjin every 30 ...

    2009.iypt.org/Buses%20to%20Tianjin.pdf‎
    Buses to Tianjin: Departure station: opposite to gate 15, first floor of the T2 opposite to gate 3, first floor of the T3. Departure time: From 7:00-23:00. The buses ...
  43. [PDF]

    Overview for Round: 5 - IYPT

    results.iypt.org/IYPT2011/roundresults-5.pdf‎
    Overview for Round: 5. Rank. Team. TSP = 1. Korea. 230.2 = 50.0 + 47.7 + 41.6 + 44.3 + 46.6. 2. Austria. 208.2 = 43.9 + 45.4 + 40.1 + 36.6 + 42.2. 3. Germany.
  44. [PDF]

    ranking after PF2 - IYPT 2008

    2008.iypt.org/PDF/PF2.pdf‎
    IYPT 2008 - CROATIA. Preliminary results after physics fight 2. Place. Team. PF1. PF2. PF3. PF4. PF5. Points. 1. Germany. 46.0. 48.7. 0.0. 0.0. 0.0. 94.7. 2.
  45. [PDF]

    ADHESIVE TAPE Stanislav Krasulin - IYPT Archive

    archive.iypt.org/iypt_book/2011_1_Adhesive_tape_Belarus_SK_v3.pdf‎
    ADHESIVE TAPE. Stanislav Krasulin. BSU Lyceum, Belarus. Introduction. This task asks us to “determine force necessary to remove a piece of adhesive tape.

  46. Round: 3 - IYPT

    results.iypt.org/AYPT2012/roundresults-3.pdf‎
    Round: 3. Rank. Team. TSP = 1. Seebacher Gym 144.2 = 51.9 + 45.9 + 46.4. 2. Bisch Gym. 142.2 = 44.7 + 46.7 + 50.8. 3. Slovakia. 140.1 = 49.1 + 46.8 + 44.2. 4.
  47. [PDF]

    Overview for Round: 1 - IYPT

    results.iypt.org/IYPT2011/roundresults-1.pdf‎
    Overview for Round: 1. Rank. Team. TSP = 1. Korea. 50.0 = 50.0. 2. Belarus. 46.9 = 46.9. 3. Singapore. 45.1 = 45.1. 4. Chinese Taipei 44.3 = 44.3. 5. Poland.
  48. [PDF]

    η - IYPT Archive

    archive.iypt.org/.../poster%20of%20problem%2016%20rotating%20spri...‎
    23rd IYPT Problem 16: Rotating Spring. Yu-Cheng Lin, Ya-Ping Chiu. Kaohsiung Municipal Kaohsiung Senior High School, Department of physics, National Sun ...
  49. [PDF]

    Round: 3, Room: Room A

    results.iypt.org/AYPT2012/previews-3.pdf‎
    Stage 1: Voronezh, Salzburg, Turkey. Problems left to challange: 1, 3, 4, 5, 7, 11, 12, 16 a) rejected by Reporter: 6 ,9 ,14 ,17 b) presented by Reporter: 10 ,13.
  50. [PDF]

    Preview for fight 1 - Room A - IYPT

    results.iypt.org/IYPT2011/previews-1.pdf‎
    Stage 1: Singapore, Bulgaria, Georgia. Problems left to challange: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,. 16, 17 a) rejected by Reporter: None.
  51. [PDF]

    Problem 05 Bright waves - iypt solutions

    solutions.iypt.org/.../2012_BR_Bright_waves_Bárbara_Cruvinel_Santiag...‎
    Jul 29, 2012 - Team of Brazil. Problem ## Title. Team of Brazil: Bárbara Santiago, Guilherme Moreira, Ibraim Rebouças, João Gabriel Faria and Liara ...
  52. [PDF]

    Overview for Round: 5

    results.iypt.org/IYPT2010/roundresults-5.pdf‎
    Overview for Round: 5. Rank. Team. TSP = 1. Singapore. 227.7 = 45.3 + 46.9 + 46.4 + 44.3 + 44.8. 2. Austria. 226.6 = 44.2 + 38.5 + 45.1 + 48.6 + 50.2. 3. Korea.
  53. [PDF]

    Preview for fight 4 - Group A

    results.iypt.org/IYPT2012/previews-4.pdf‎
    Stage 1: Slovakia, Bulgaria, Russia. Problems left to challange: 2, 6, 7, 9, 11, 12, 15, 16, 17 a) rejected by Reporter: 10 ,13 b) presented by Reporter: 1 ,4 ,8.
  54. [PDF]

    Overview for Round: 2 - IYPT

    results.iypt.org/IYPT2011/roundresults-2.pdf‎
    Overview for Round: 2. Rank. Team. TSP = 1. Korea. 97.7 = 50.0 + 47.7. 2. Austria. 89.3 = 43.9 + 45.4. 3. Belarus. 86.3 = 46.9 + 39.4. 4. Chinese Taipei 84.1 ...
  55. [PDF]

    Round: 1, Room: Room D

    results.iypt.org/test/previews-1.pdf‎
    Stage 1: Voronezh, Slovakia, Turkey. Problems left to challange: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,. 16, 17 a) rejected by Reporter: None b) presented ...
  56. [PDF]

    Overview for Round: 2

    results.iypt.org/IYPT2012/roundresults-2.pdf‎
    Overview for Round: 2. Rank. Team. TSP = 1. Korea. 88.9 = 44.7 + 44.2. 2. Singapore. 82.8 = 40.1 + 42.7. 3. Iran. 78.9 = 34.8 + 44.1. 4. Switzerland. 78.8 = 37.2 ...
  57. [PDF]

    f - iypt solutions

    solutions.iypt.org/.../2012_BY_Cutting_the_air_Anton_Khvalyuk_1344...‎
    The problem. When a piece of thread (e.g., nylon) is whirled aroundwith a small mass attached to its free end, a distinct noise is emitted. Study the originof this.
  58. [PDF]

    Round: 2 - IYPT

    results.iypt.org/AYPT2011/roundresults-2.pdf‎
    Round: 2. Rank. Team. TSP = 1. Seebacher Gymnasium Graz. 102.6 = 48.1 + 54.5. 2. Bischoefliches Gymnasium Graz 92.5 = 45.0 + 47.5. 3. Belarus.
  59. [PDF]

    Overview for Round: 4 - IYPT

    results.iypt.org/IYPT2012/roundresults-4.pdf‎
    Overview for Round: 4. Rank. Team. TSP = 1. Korea. 179.9 = 44.7 + 44.2 + 41.5 + 49.5. 2. Singapore. 169.2 = 40.1 + 42.7 + 44.0 + 42.4. 3. Iran. 161.6 = 34.8 + ...
  60. [PDF]

    Round: 2 - IYPT

    results.iypt.org/AYPT2012/roundresults-2.pdf‎
    Round: 2. Rank. Team. TSP = 1. Seebacher Gym 97.8 = 51.9 + 45.9. 2. Slovakia. 95.9 = 49.1 + 46.8. 3. Iran. 92.4 = 43.9 + 48.5. 4. Bisch Gym. 91.4 = 44.7 + 46.7.
  61. [PDF]

    Structure of soap film - iypt solutions

    solutions.iypt.org/.../2010_GE_Soap_film_Alexander_Barnaveli_13520...‎
    №4. Soap film. Create a soap film in a circular wire loop. The soap film deforms when a charged body is placed next to it. Investigate how the shape of the soap ...
  62. [PDF]

    Dynamic Bubbles - IYPT

    solutions.iypt.org/.../2012_KR_Bubbles_Hyung_Ju_Suh_1351552704.p...‎
    Problem Statement. Is it possible to float on water when there are a large number of bubbles present? Study how the buoyancy of an object depends on the ...
  63. [PDF]

    l - IYPT Archive

    archive.iypt.org/.../poster%20of%20problem%2014%20%20magnetic%...‎
    Comprehensive solution of . 23rd IYPT Problem : Magnetic Spring. Tsung-Lin Hsieh and Chien-Rong Lu. Taipei Municipal Jianguo High School and Department ...
  64. [PDF]

    Overview for Round: 4 - IYPT

    results.iypt.org/IYPT2011/roundresults-4.pdf‎
    Overview for Round: 4. Rank. Team. TSP = 1. Korea. 183.6 = 50.0 + 47.7 + 41.6 + 44.3. 2. Germany. 166.5 = 40.5 + 41.9 + 42.6 + 41.5. 3. Austria. 166.0 = 43.9 + ...
  65. [PDF]

    Overview for Round: 3 - IYPT

    results.iypt.org/IYPT2011/roundresults-3.pdf‎
    Overview for Round: 3. Rank. Team. TSP = 1. Korea. 139.3 = 50.0 + 47.7 + 41.6. 2. Austria. 129.4 = 43.9 + 45.4 + 40.1. 3. Germany. 125.0 = 40.5 + 41.9 + 42.6. 4.
  66. [PDF]

    x - iypt solutions

    solutions.iypt.org/.../2012_KR_Bright_waves_Hyung_Ju_Suh_1351552...‎
    Page 1. Page 2. Page 3. i θ f θ air air v c n = water water v c n. = f water i air n n θ θ sin sin = Page 4. Change of Surface. Curvature! Unequal Distribution of ...
  67. [PDF]

    ranking after pf5 - IYPT

    2008.iypt.org/PDF/PF5.pdf‎
    Place. Team. PF1. PF2. PF3. PF4. PF5. Points. Team #. 1. Germany. 46.0. 48.7. 48.2. 47.0. 45.7. 235.6. 16. 2. New Zealand. 43.5. 43.0. 44.6. 47.8. 49.4. 228.3.
  68. [PDF]

    A report should include:

    results.iypt.org/IYPT2012/SG/round4groupH.pdf‎
    Nov 3, 2011 - Room: Fight (Round no.): A report should include: o a presentation of the appropriate concepts, theories and principles of the problem 0 an ...
  69. [PDF]

    A report should include: - IYPT

    results.iypt.org/IYPT2012/SG/round1groupD.pdf‎
    Nov 3, 2011 - Juror: A report should include: a a presentation of the appropriate. concepts, theories and principles of the problem I an explanation of the ...
  70. [PDF]

    u re

    results.iypt.org/IYPT2012/SG/round4groupK.pdf‎
    Nov 3, 2011 - u re. Fight (Round no.): Room: Stage: 5 Problem no;. 6/ v '. Juror: A report should include: 0 a presentation of the appropriate concepts, theories ...
  71. [PDF]

    FightlRound no): i/ “M” Stage: “'

    results.iypt.org/IYPT2012/SG/round4groupC.pdf‎
    is a;. FightlRound no): i/ “M” Stage: “'. Juror: Signature: __.______.?______. Room: rin. A report should include: v a presentation of the appropriate concepts, ...
  72. [PDF]

    Scoring Guidelines - IYPT

    results.iypt.org/IYPT2012/SG/round5groupG.pdf‎
    Z“ I. Fight(Round no.): J Room: Q Stage:, I Problem no.: Scoring Guidelines. Juror: Y A L:§;}€'/A Signature: ~72\; M. A report should include: i» a presentation of ...
  73. [PDF]

    Fight (Round no): Stage: - IYPT

    results.iypt.org/IYPT2012/SG/round4groupE.pdf‎
    Nov 3, 2011 - Fight (Round no): Stage: me,. “x. Juror Signature: if. A report should include: 0 a presentation of the appropriate concepts, theories and ...
  74. [PDF]

    _ 5;»; . j; . . 1%

    results.iypt.org/IYPT2012/SG/round2groupH.pdf‎
    AWE Contribution to the discussion fr? 4'; frank'. _ 5;»; . j; . . 1%. Fina] Grade; Reporter Final Grade: Opponent Final Grade: Reviewer 'e'. ' ' ' a'. Q/Signature: I.
  75. [PDF]

    ui - IYPT

    results.iypt.org/IYPT2012/SG/round1groupK.pdf‎
    Nov 3, 2011 - Fight (Round no): m. Juror: rl/ ui. A report should include: a a presentation of the appropriate concepts, theories and principles of the problem 0 ...
  76. [PDF]

    1 ; Signature:

    results.iypt.org/IYPT2012/SG/round1groupF.pdf‎
    Nov 3, 2011 - 1 ; Signature: Fight(Roundno.): 'Xg Room: Stage: Pr0blemno1l>2. A report should include: I a presentation of the appropriate concepts, theories ...
  77. [PDF]

    Fight (Round no): 3*" Stage:

    results.iypt.org/IYPT2012/SG/round2groupE.pdf‎
    Fight (Round no): 3*" Stage: Juror: Signature: “ii. “lama” i". A report should include: e a presentation of the appropriate concepts, theories and principles of the ...
  78. [PDF]

    ui

    results.iypt.org/IYPT2012/SG/round3groupE.pdf‎
    Nov 3, 2011 - ui. Room: Li. Fight (Round no.): Juror: , A l“: Stage: Problemnoyfz b. , '4“? Signature: [,4W. r l. » i. A report should include: 0 a presentation of the ...
  79. [PDF]

    FightlRound no.): Room: Stage: A

    results.iypt.org/IYPT2012/SG/round5groupA.pdf‎
    Nov 3, 2011 - I'M A g ,. FightlRound no.): Room: Stage: A v Juror: Signature: cf. Problem nor:w. A report should include: 0 a presentation of the appropriate ...
  80. [PDF]

    Page 1 ti \ Room: '3 / Fight (Round no): v Stage: / r“ " *1/44: . Juror ...

    results.iypt.org/IYPT2012/SG/round5groupE.pdf‎
    Nov 3, 2011 - ti. \ Room: '3. /. Fight (Round no): v Stage: / r“ " *1/44: . Juror: {Li B b i Signature: A report should include: Q a presentation of the appropriate ...
  81. [PDF]

    K A - IYPT

    results.iypt.org/IYPT2012/SG/round2groupK.pdf‎
    K A. Stage: Problem no.: if? n E Signature: 5' ' f “in” g. /. Fight (Round no): Room: Juror: . Guidelines. A report should include: o a presentation of the appropriate ...
  82. [PDF]

    Signatu re: '; a/

    results.iypt.org/IYPT2012/SG/round3groupF.pdf‎
    Nov 3, 2011 - Signatu re: '; a/. Stage: A report should include: 0 a presentation of the appropriate concepts, theories and principles of the problem 0 an ...
  83. [PDF]

    {we a“ W Juror: i oval/var Signature: MW 6 , - IYPT

    results.iypt.org/IYPT2012/SG/round3groupI.pdf‎
    Nov 3, 2011 - Fight (Round no): Room: 6» Stage: r. {we a“ W Juror: i oval/var Signature: MW 6 ,. Isl/Ages. A report should include: 0 a presentation of the ...
  84. [PDF]

    cring - IYPT

    results.iypt.org/IYPT2012/SG/round1groupH.pdf‎
    we. Juror: r \1 ~, cring. Signature: A , ,1,. FightiRound no): i'i Room: i'i; Stage: i Problem not: 5*. A report should include: 0 a presentation of the appropriate ...
  85. [PDF]

    Fight (Round no): in

    results.iypt.org/IYPT2012/SG/round3groupA.pdf‎
    Nov 3, 2011 - Fight (Round no): in. Room: i la”. Signature: imp—'2'". A report should include: An opposition should show that: a a presentation of the ...
  86. [PDF]

    iii - IYPT

    results.iypt.org/IYPT2012/SG/round5groupB.pdf‎
    iii. Stage: Fight (Round no): if;. Juror Signature: Problem no.: A report should include: o a presentation of the appropriate concepts, theories and principles of the ...
  87. [PDF]

    ML - IYPT

    results.iypt.org/IYPT2012/SG/round2groupA.pdf‎
    Room: Stage: g Problem no.2. Fight (Round no.): ML. ' ring iurorffél éijfiliil Signature: Q} 5%“WWW. A report should include: 0 a presentation of the appropriate ...
  88. [PDF]

    _\ Fight (Round no):

    results.iypt.org/IYPT2012/SG/round2groupF.pdf‎
    Nov 3, 2011 - _\. Fight (Round no): c I' Q' I I' ' V <11"? Juror: ' V? j; , Si nature: 2. Room: /dl Stage: Problemnocz l coring Guidelines. A report should include:.
  89. [PDF]

    C a

    results.iypt.org/IYPT2012/SG/round1groupC.pdf‎
    or“ 6 of the re ort e to i s repented or discussed. Explanation of formulae and p symbols MM [ii Finds shortcomings or errors in El Relevance of uestions to both ...
  90. [PDF]

    Fight(Roundno.): ii Room: E Stage: 3

    results.iypt.org/IYPT2012/SG/round1groupE.pdf‎
    Fight(Roundno.): ii Room: E Stage: 3 swoop,. Problem no: 7L. A report should include: 0 a presentation of the appropriate concepts, theories and principles of ...
  91. [PDF]

    Scoring Guidelines

    results.iypt.org/IYPT2012/SG/round2groupC.pdf‎
    Scoring Guidelines. Z. Fight (Round no): Room: Juror. Signature: Stage: l i. A report should include: e a presentation of the appropriate concepts, theories and ...
  92. [PDF]

    ri uidelins

    results.iypt.org/IYPT2012/SG/round2groupB.pdf‎
    ri uidelins. A report should include: - a presentation of the appropriate concepts, theories and principles of the problem Q an explanation of the observed ...
  93. [PDF]

    f

    results.iypt.org/IYPT2012/SG/round3groupD.pdf‎
    Nov 3, 2011 - Fight(Round no): “i; Roomzwg Stage: /f f. Problem ho; \D. Juror: Signature: 5&7: A report should include: 0 a presentation of the appropriate ...
  94. [PDF]

    Fight(Round no): '2 Room: @2 Stage: v Problem no - IYPT

    results.iypt.org/IYPT2012/SG/round2groupG.pdf‎
    Fight(Round no): '2 Room: @2 Stage: v Problem no,:__. I x /',/'s.»»'-"' l _ in. Juror \ r. A report should include: 0 a presentation of the appropriate concepts, ...
  95. [PDF]

    Fight(Round no): Room: Stage: 5 Problem no: Juror 1", x lZTUi/Léi ...

    results.iypt.org/IYPT2012/SG/round5groupD.pdf‎
    Nov 3, 2011 - 3 \\. Fight(Round no): Room: Stage: 5 Problem no: Juror 1", x lZTUi/Léi iliieo Signature: c'ZQawm. A,. A report should include: Q a presentation ...
  96. [PDF]

    '- r . - IYPT

    results.iypt.org/IYPT2012/SG/round4groupF.pdf‎
    Jr. Fight(Roundno.): P? Room: '- r . w Stage: A Problernno: 3. Signature: .luror: ". A report should include: 0 a presentation of the appropriate concepts, theories ...
  97. [PDF]

    iii, iii: i;

    results.iypt.org/IYPT2012/SG/round4groupB.pdf‎
    Nov 3, 2011 - Fight (Round no): Juror: all Room: if»: Stage: y Problemno,:_. Signature: iii, iii: i; f ill/damn “WW'. A report should include: Q a presentation of the ...
  98. [PDF]

    ri - IYPT

    results.iypt.org/IYPT2012/SG/round4groupG.pdf‎
    is” El. Fight(Roundno.): Room: Stage: ~ lin ri. A report should include: a a presentation of the appropriate concepts, theories and principles of the problem v an ...


No comments:
Subscribe to: Posts (Atom)